Re: useradd -p

[Danny Sauer <sauer@cloudmaster.com>]

Are you on a system that uses MD5 passwords or something like that?
I've done that exact thing before (except for using my own random
function just to spite the String::Random author ;)) and it worked
fine.  I suggest the use of single quotes, to protect shell metachars
and make the code cleaner.  If you're sure that the value getting put
into /etc/shadow is the same as the one the program generates, then 
that's not your problem.

--Danny, merely dumping thoughts that might help 

On Mon, Apr 01, 2002 at 03:51:00PM -0600, Charles Menzes wrote:
> 
> the man page for useradd shows that the '-p' flag  is used to specify an 
> already encrypted password string as as returned by crypt(3).
> 
> in my (very) simple perl script, i have:
> 
>     ## generate random characters
>     my $random = new String::Random;
> 
>     ## salt the passwd
>     my $salt = $random->randpattern("ss");
> 
>     ## encrypt the password
>     my $crypt = crypt($first_pass, $salt);
> 
>     ## return encrypted password to root routine
>     return ($crypt);
> 
> this just passes teh value of $crypt to a system call to 'useradd' that 
> uses /-p "$crypt"/. the user is added to the system and the string passed 
> through -p is used in /etc/shadow, however when i try to log in as the 
> user, i get an error of incorrect password. my system call is...
> 
>   system("/usr/sbin/useradd -c \"$gecos\" -d $home -G $gid -s $shell -p 
> \"$password\" $username");
> 
> am i missing something in the useradd usage or in perl?
> 
> 
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