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the man page for useradd shows that the '-p' flag is used to specify an
already encrypted password string as as returned by crypt(3).
in my (very) simple perl script, i have:
## generate random characters
my $random = new String::Random;
## salt the passwd
my $salt = $random->randpattern("ss");
## encrypt the password
my $crypt = crypt($first_pass, $salt);
## return encrypted password to root routine
this just passes teh value of $crypt to a system call to 'useradd' that
uses /-p "$crypt"/. the user is added to the system and the string passed
through -p is used in /etc/shadow, however when i try to log in as the
user, i get an error of incorrect password. my system call is...
system("/usr/sbin/useradd -c \"$gecos\" -d $home -G $gid -s $shell -p
am i missing something in the useradd usage or in perl?
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